1

I have a below Data Frame and would like to subset the dataframe which has the last business day of the month to separate data frame.

df = Date Open High Low Close Adj Close Volume 0 2007-06-18 0.33979 0.33979 0.33979 0.33979 0.33979 1591888 1 2007-06-29 0.33074 0.33074 0.33074 0.33074 0.33074 88440 2 2007-06-20 0.33526 0.33526 0.33526 0.33526 0.33526 3538 3 2007-06-21 0.32113 0.32113 0.32113 0.32113 0.32113 3550 4 2007-06-22 0.34713 0.34713 0.34713 0.34713 0.34713 670

df_output =

Date Open High Low Close Adj Close Volume 1 2007-06-29 0.33074 0.33074 0.33074 0.33074 0.33074 88440

I have tried df = pd.to_datetime(df['Date'], format='%Y%m%d') + pd.offsets.BMonthEnd(1) but is not working and I have looked to here but did not find the right approach. Can anyone help me in solving this.

Alex_MN
  • 155
  • 2
  • 9

1 Answers1

2

You could do it like this:

# in case Date is not in datetime format:
df['Date'] = pd.to_datetime(df['Date'])

df_output = df.loc[df.Date.isin(df.Date + pd.offsets.BMonthEnd(1))]

This returns:

>>> df_output
        Date     Open     High      Low    Close  Adj Close  Volume
1 2007-06-29  0.33074  0.33074  0.33074  0.33074    0.33074   88440

Explanation:

df.Date + pd.offsets.BMonthEnd(1) returns a series of the last business day in each month for which you have data:

>>> df.Date + pd.offsets.BMonthEnd(1)
0   2007-06-29
1   2007-07-31
2   2007-06-29
3   2007-06-29
4   2007-06-29

Then, you use loc to locate any rows in your dataframe in which the actual Date is in that series (using .isin)

sacuL
  • 49,704
  • 8
  • 81
  • 106