Tidy function is not working with USAboundaries shapefile data

Question

I'm not understanding what the error is as the tidy function works fine with other shapefiles, is USAboundaries missing something?

library(USAboundaries)
library(broom)

states_dat <- tidy(us_states(), region = "geoid")

##> states_dat <- tidy(us_states(), region = "geoid")
##Error in psych::describe(x, ...) : unused argument (region = "geoid")

head(us_states()[4],3)

##> head(us_states()[4],3)
##   geoid
##1     23
##2     15
##3     04

I don't know the `tidy()` function, but for what I can see the column names goes to one column named "column", and the other columns are some statistics of theses variables... Is this correct? — cirofdo, May 24 '18 at 17:54

score 1 · Accepted Answer · answered May 24 '18 at 18:54

us_states() returns an sf object. tidy has no method for sf objects and uses the data.frame method instead. On the other hand, tidy has methods for a variety of classes from the sp package, which may be why it "works fine with other shapefiles." (See help(sp_tidiers).)

To use your existing code, you can convert the us_states() output to a Spatial object:

library(sf)
states <- as(us_states(), "Spatial")
states_dat <- tidy(states, region = "geoid")

To learn how to work with sf objects in a tidy framework, you may find http://strimas.com/r/tidy-sf/ helpful.

Tidy function is not working with USAboundaries shapefile data

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