Currying func and keep param name/ label in Swift 4

Question

In Swift 4, how can I curry func, and keep param label/ name:

func doSomething(a: A, b: B, c: C) {
}

let do_a = doSomething(a: value_a) // keep name a
let do_ab = do_a(b: value_b) // keep name b
let result = do_ab(c: value_c) // keep name c

With the answer from here Curry Function in Swift

And https://robots.thoughtbot.com/introduction-to-function-currying-in-swift

I can do, but the label is omitted

let curryDo = curry(doSomething)
let doA = curryDo(value_a) // but the a label is removed here.

How to keep param label/name in currying func?

score 1 · Answer 1 · answered May 23 '18 at 07:26

1

Swift removed currying as a feature in version 3, and all current implementations use closures, which don't have labeled arguments.

answered May 23 '18 at 07:26

Avi

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Thank you. Still waiting for a solution. T_T – tuledev May 23 '18 at 07:41
@anhtu, Propose re-introducing currying on Swift Evolution. If no one steps up, nothing will happen. – Avi May 23 '18 at 10:19

Currying func and keep param name/ label in Swift 4

1 Answers1