Create instance of struct with values

Question

// Valid checks Config data
func (c *Config) Valid() Error {
    // Check mapping.hosts
    for _, raw := range c.Mapping.Hosts {
        if validIP := utils.ValidIP4(raw.IPAddress); !validIP {
            err := new(InvalidIPError)
            return err
        }
    }

    return nil
}

// Error represents errors in config
type Error interface {
    Error() string
}

// InvalidIPError raises when invalid ip provided
type InvalidIPError struct {
    HostRaw HostRaw
}

func (e *InvalidIPError) Error() string {
    return fmt.Sprintf("You specified invalid IP: %v", e.HostRaw)
}

How I can create instance of InvalidIPError with new keyword and values to send it to return in one line?

For example something like this return new(InvalidIPError{HostRaw: raw})

You can't using `new`, but you don't have to use `new`. Try taking the [Tour of Go](https://tour.golang.org). — Adrian, May 21 '18 at 18:13
Possible duplicate of https://stackoverflow.com/questions/4498998/how-to-initialize-members-in-go-struct, — Charlie Tumahai, May 21 '18 at 18:29

score -1 · Answer 1 · answered May 21 '18 at 18:19

-1

return &InvalidIPError{HostRaw: raw}

answered May 21 '18 at 18:19

user3169724

39
7

3

More detail as to *why* this solves the question would be very useful to other readers in the future. – Joe McMahon May 21 '18 at 19:49

Create instance of struct with values

1 Answers1