URL patterns in Django 2

Question

I just have started my first project by using Django 2.0 in which I need to define a URL in a way as: http://localhost:8000/navigator?search_term=arrow

But I couldn't know how to define a string parameter for a URL in Django 2.0

Here's what I have tried:

From ulrs.py:

from Django.URLs import path from. import views

urlpatterns = [
    path('navigator/<str:search_term>', views.GhNavigator, name='navigator'),

]

Any help?

It doesn't matter which version of Django you use, query string values are still not part of the URL. — Daniel Roseman, May 21 '18 at 17:23
Hi @DanielRoseman, this is not actually a query string, I just need to grab a search term from the user to use it for Github API. — Abdul Rehman, May 21 '18 at 17:24
So, is there any way I can get a string from users in a url? — Abdul Rehman, May 21 '18 at 17:26

score 8 · Accepted Answer · edited May 21 '18 at 17:39

8

There is no need to define query params in URL. Below url is enough to work.

path('navigator/', views.GhNavigator, name='navigator')

Let you called URL http://localhost:8000/navigator/?search_term=arrow then you can get search_term by request.GET.get('search_term').

edited May 21 '18 at 17:39

Daniel Roseman

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answered May 21 '18 at 17:29

SHIVAM JINDAL

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score 0 · Answer 2 · answered Dec 22 '20 at 13:16

0

Request: GET

http://localhost:8000/navigator?search_term=arrow

urls.py

urlpatterns = [
    path('navigator/', views.GhNavigator, name='navigator'),
]

views.py

search_term = request.GET.get('search_term', None)

answered Dec 22 '20 at 13:16

Hasan Khan

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URL patterns in Django 2

2 Answers2