I got the json data from the url and I need to print the json data in my laravel 5.6 view

Question

Trying to print the json data in my laravel5.6 view using controller. I got an error

Illegal string offset 'rates'

My Controller Code

 $req_url = 'https://v3.exchangerate-api.com/bulk/6eea6e74c3abe1df9de390c2/USD';
 $response_json = file_get_contents($req_url);
 $configdata4   = json_encode($response_json);
 $final_data4 = json_decode($configdata4,true);
 return view('clientlayout.main.registerdomain',compact('final_data4'));

My view page Code

@foreach($final_data4['rates'] as $value)
{{$value['USD']}}
@endforeach

Please suggest any solutions to this issue.

[This](https://stackoverflow.com/questions/9869150/illegal-string-offset-warning-php) might be useful. — Parth Pandya, May 19 '18 at 10:08

score 2 · Answer 1 · answered May 19 '18 at 10:06

No need to use json_encode. You are already getting as json format

 $req_url = 'https://v3.exchangerate-api.com/bulk/6eea6e74c3abe1df9de390c2/USD';
 $response_json = file_get_contents($req_url);
 $final_data4 = json_decode($response_json,true);
 return view('clientlayout.main.registerdomain',compact('final_data4'));

Live Demo

score 1 · Accepted Answer · answered May 19 '18 at 10:08

1

Your already get the response in json format, all you need to do is to decode and return it, as the following:

$req_url = 'https://v3.exchangerate-api.com/bulk/6eea6e74c3abe1df9de390c2/USD';
$response_json = file_get_contents($req_url);
$final_data4 = json_decode($response_json);
return view('clientlayout.main.registerdomain',compact('final_data4'));

answered May 19 '18 at 10:08

Firas Rassas

509
4
12

add second param as `true` as OP uses as array here `json_decode($response_json,true)` – Niklesh Raut May 19 '18 at 10:16

I got the json data from the url and I need to print the json data in my laravel 5.6 view

2 Answers2