Regex Find & Replace LowercaseUppercase

Question

I'm looking to find and replace "agoWhen" with:

"ago\nWhen"

I can find with [a-z][A-Z], but how do I replace with a line break?

This is to fix a large plain text document in the macOS app Coda. — user3158128, May 18 '18 at 22:26
Not sure about coda, But Typical regex:`([a-z])([A-Z])` replacement: `$1\n$2` — TheMaster, May 18 '18 at 22:54

score 0 · Answer 1 · answered May 19 '18 at 00:27

I think you can use regex to find the pattern and then apply for loops to get the desired format.

def insert_new_line(text):
    result = []
    for match in re.findall('[a-z]+[A-Z][a-z]+', text):
        for index in range(len((match))):
            if match[index].isupper():
                result.append(match[:index]+'\n' +match[index:])
    #return resresult
    return ' '.join(result)

For example;

print(insert_new_line('thisMan is not inClass'))

returns;

this
Man in
Class

And if you want a list of all the matches returned, you could simply replace the return line of the function with;

return result

in which case;

print(insert_new_line('thisMan is not inClass'))

returns;

['this\nMan', 'in\nClass']

Let me know if this helps.

Regex Find & Replace LowercaseUppercase

1 Answers1