where is the error in my code trying to compare case -insensitive using python

Question

I have a code that read files and compare the content with a user-input with ignoring case-sensitive.

i used the list-comprehension in order to loop through the content and compare with user-input.

The problem is that the list comprehension return an empty list, although the entered word exist. Example:

textContent

Les hiboux Charles Baudelaire

Cycle 3 *

POESIE

Sous les ifs noirs qui les abritent Les hiboux se tiennent rangés Ainsi que des dieux étrangers Dardant leur œil rouge. Ils méditent.

Sans remuer ils se tiendront Jusqu'à l'heure mélancolique Où, poussant le soleil oblique, Les ténèbres s'établiront.

Leur attitude au sage enseigne Qu'il faut en ce monde qu'il craigne Le tumulte et le mouvement ;

L'homme ivre d'une ombre qui passe Porte toujours le châtiment D'avoir voulu changer de place.

Les Fleurs du Mal 1857

Charles Pierre Baudelaire (1821 – 1867) est un poète français.

user-input: charl
word exist : Charles--charle--CHARLE

x=self.lineEditSearch.text()
print(x)
textString=self.ReadingFileContent(Item)

#self.varStr =[c for c in textString if c.islower() or c.isupper() or c.capitalize()]            
self.varStr =[i for i in textString if i.lower() == x.lower()]            

print(self.varStr)

Try to make a minimal example that is executable but doesn't work. Like this, one cannot run your example because "self" is not defined. — Martin Thoma, May 18 '18 at 05:48
None of the words "Charles", "charle" and "CHARLE" are equal to "charl", so an empty list is the correct output. — Aran-Fey, May 18 '18 at 05:49
Do you mean to `zip(textString, x)`? This question is very confusing. — Mateen Ulhaq, May 18 '18 at 05:49
@Aran-Fey how is neither one is equal to charl ?--- what i expect is to get a part of each word isn't that correct ? — Propy Propy, May 18 '18 at 05:55
@MateenUlhaq no there is no zip i just need to compare user-input with text content — Propy Propy, May 18 '18 at 06:11

score 0 · Answer 1 · answered May 18 '18 at 06:10

0

If

user_input = "charl"
word_exist = ["Charles","charle","CHARLE","Hello"]

Then

output = [item for item in word_exist if user_input.lower() in item.lower()]
print(output)
# ['Charles', 'charle', 'CHARLE']

Is this what you are looking for?

answered May 18 '18 at 06:10

Shivam Singh

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YES without using regular expression – Propy Propy May 18 '18 at 06:27
This does not use regular expression – Shivam Singh May 18 '18 at 06:28
Please give a minimal example that can be run, like what your values for `x` and `textString` – Shivam Singh May 18 '18 at 06:40
that is what i did in the example that i give where **x is = charl** and **textString = textContent** i will edit my question and add the content of textString – Propy Propy May 18 '18 at 06:47
`textString = "Charles--charle--CHARLE"` ? Like words separated by "--"? – Shivam Singh May 18 '18 at 06:49
textString = to text the separation parameter is **space** – Propy Propy May 18 '18 at 07:03

score 0 · Answer 2 · answered May 18 '18 at 06:15

Your problem is, you are only putting in self.varStr members of textString that satisfies i.lower() == x.lower(), which means "being completely the same (case insensitive) with x".

You want to pick up members that contains x.

You can do that by changing i.lower() == x.lower() into i.lower() in x.lower()

where is the error in my code trying to compare case -insensitive using python

textContent

2 Answers2