I have numerous Bokeh Server files in a directory say.. /dir/bokeh/
, assume the bokeh servers are called bokeh1.py, bokeh2.py, bokeh3.py
The file structure is like so:
|--dir
|---flask.py
|---bokeh
|--bokeh1.py
|--bokeh2.py
I am deploying them all on flask like so:
files=[]
for file in os.listdir("/dir/bokeh/"):
if file.endswith('.py'):
file="bokeh/"+file
files.append(file)
argvs = {}
urls = []
for i in files:
argvs[i] = None
urls.append(i.split('\\')[-1].split('.')[0])
host = 'myhost.com'
apps = build_single_handler_applications(files, argvs)
bokeh_tornado = BokehTornado(apps, extra_websocket_origins=["myhost.com"])
bokeh_http = HTTPServer(bokeh_tornado)
sockets, port = bind_sockets("myhost.com", 0)
bokeh_http.add_sockets(sockets)
Then for each bokeh server, I have within flask.py
:
@app.route("/bokeh1")
def bokeh1():
bokeh_script = server_document("http://11.111.11.111:%d/bokeh1" % port)
return render_template("bokserv.html", bokeh_script=bokeh_script)
The number of bokeh servers I need to deploy could grow quickly. How can I write something that will generate the @app.route
for each of the bokehs bokeh1.py, bokeh2.py, bokeh3.py
efficiently based on my current setup? The server is being run on Ubuntu