I have an example string:
var string= ">ACK;ID=1206;#01D4;";
I need to calculate CheckSum 8 Xor so that it returns me 2 digits in hex:
answer: 2B
Can you help me?
Asked
Active
Viewed 4,068 times
0
mplungjan
- 169,008
- 28
- 173
- 236
Carlos Alexandre R Ramos
- 1
- 1
- 2
-
Please show the actual string in a string format. I do not get 2b if I calculate the checksum on `>ACK;ID=1206;#01D4` or on `ACK;ID=1206;#01D4` – mplungjan May 07 '18 at 14:21
-
https://www.scadacore.com/tools/programming-calculators/online-checksum-calculator/ – mplungjan May 07 '18 at 14:21
-
Likely duplicate of https://stackoverflow.com/questions/48328603/8-bit-xor-checksum-using-javascript?utm_medium=organic&utm_source=google_rich_qa&utm_campaign=google_rich_qa – mplungjan May 07 '18 at 14:21
-
The estring and the one that I put in the example, I got the result after calculating in an online calculator and in 8bits it was 2B – Carlos Alexandre R Ramos May 07 '18 at 14:37
-
What is the actual string. *I* added the quotes - are they added correctly? `>ACK;ID=1206;#01D4` is your string? – mplungjan May 07 '18 at 14:41
-
yes this is the string >ACK;ID=1206;#01D4 – Carlos Alexandre R Ramos May 07 '18 at 14:53
-
Show me the place where you got 2B – mplungjan May 07 '18 at 16:38
-
I inserted an image of the calculator – Carlos Alexandre R Ramos May 09 '18 at 12:41
-
Your string is `>ACK;ID=1206;#01D4;` not `>ACK;ID=1206;#01D4` – mplungjan May 09 '18 at 12:42
-
So it IS a duplicate of https://stackoverflow.com/questions/48328603/8-bit-xor-checksum-using-javascript - why did you not try that? – mplungjan May 09 '18 at 12:44
-
I tried even more so I did not validate and it presents me differently, it simply converts all the characters to hex and returns me – Carlos Alexandre R Ramos May 09 '18 at 12:53
-
Good afternoon folks Thanks in advance for the attention of all, but I have succeeded with the example of the link below, thank you already. https://stackoverflow.com/questions/48328603/8-bit-xor-checksum-using-javascript?utm_medium=organic&utm_source=google_rich_qa&utm_campaign=google_rich_qa – Carlos Alexandre R Ramos May 11 '18 at 19:31
-
Feel free to delete – mplungjan May 11 '18 at 19:34