Checking if long is in array

Question

I need to make sure that a certain long value isn't in an array. But for some reason, this isn't working...

!d.toString().contains(sq.toString());

I am sure I am getting something really backwards... but I can't figure out what!

Assuming that `d` is actually the array, then `.toString()` is not going to do what you're thinking -- it's not going to print out the elements of the array, and thus testing `contains` on that string is useless. — Kirk Woll, Feb 15 '11 at 22:05
I would suggest checking for equality instead contains because: `"12345".contains("123")` returns `true` which is probably not what you want (assuming `d` and `sq` are string representations of the longs). — armandino, Feb 15 '11 at 22:07

score 7 · Accepted Answer · answered Feb 15 '11 at 22:06

7

Try

!Arrays.asList(d).contains(sq);

answered Feb 15 '11 at 22:06

Bala R

4

Attention: this does not work for a `long[]`, only for object-type arrays (like `Long[]`). – Paŭlo Ebermann Feb 16 '11 at 09:58

score 0 · Answer 2 · answered Feb 15 '11 at 22:04

0

Look at the static methods in java.util.Arrays. Your array will need to be sorted for the binarySearch() to work.

answered Feb 15 '11 at 22:04

Chesrae

2 Answers2