How to get resource path in flask-RESTPlus?

Question

I am fairly new at working with flask and flask-RESTPlus. I have the following and it is not clear how can I determine which path was used in the get request?

ns = api.namespace('sample', description='get stuff')

@ns.route(
    '/resource-settings/<string:address>',
    '/unit-settings/<string:address>',
    '/resource-proposals/<string:address>',
    '/unit-proposals/<string:address>')
@ns.param('address', 'The address to decode')
class Decode(Resource):
    @ns.doc(id='Get the decoded result of a block address')
    def get(self, address):
        # How do I know what get path was called?
        pass

score 1 · Answer 1 · answered Apr 29 '18 at 12:53

1

Through lot's of digging I found that url_for in flask import.

Still feels a bit wonky but I can create a fully qualified link with:

result = api.base_url + url_for('resource-settings', address=id)

So this works and I get the desired results.

answered Apr 29 '18 at 12:53

Frank C.

7,758
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score 1 · Accepted Answer · answered Jun 07 '18 at 16:37

1

A better solution would be to use the request context. To get the full path, you can do:

from flask import request

def get(self, address):
    # How do I know what get path was called?
    print(request.full_path)

answered Jun 07 '18 at 16:37

dmulter

2,608
3
15
24

Yes, is better. Thanks! – Frank C. Jun 08 '18 at 08:03

How to get resource path in flask-RESTPlus?

2 Answers2