How can I set UIPickerView at other than the default index?

Question

I have an integer having value of 5 and I want to start my UIPickerView with this index, now what should I do? normally UIPickerView is on default 0 index row, but I want it on index which is user defined, as can be 5, 6 or any other digit.

score 47 · Accepted Answer · answered Feb 15 '11 at 13:57

47

Assuming your picker is referred to in a property "myPicker", then in viewDidLoad, go:

[self.myPicker selectRow:rowInt inComponent:componentInt animated:NO]

answered Feb 15 '11 at 13:57

Dan Ray

21,623
6
63
87

what are rowInt and componentInt ? – Chatar Veer Suthar Feb 17 '11 at 05:01
2

they're integers saying what row of what component you want to pre-select. – Dan Ray Feb 17 '11 at 13:08
what do you mean by inComponent? – Dejell Mar 11 '14 at 16:12
1

A picker can have more than one "wheel". The default date picker is a good example--it has separate spinner sections for date, hour, minute, etc (depending on how you configure it). In Cocoa-Touch-ese, those are "components". – Dan Ray Mar 12 '14 at 13:42
if I want to select first item from picker-view what should pass in parameter – Bhumesh Purohit Apr 12 '18 at 12:02

score 1 · Answer 2 · answered Jan 08 '19 at 00:09

1

Update for Swift 4.2:

To set the default row in a UIPickerView,

  myPicker.selectRow(5, inComponent: 0, animated: true)

where myPicker is the name of the UIPickerView and 5 is the index of the desired row.

answered Jan 08 '19 at 00:09

Marcy

4,611
2
34
52

How can I set UIPickerView at other than the default index?

2 Answers2