Disable NSButton without grayed image

Question

I want to disable the user interaction of NSButton. The only possible option seems to be setting isEnabled to false:

button.isEnabled = false

...but the problem is that it's giving a white shade to the image of my button. Is there any way to get rid of that shade?

score 8 · Accepted Answer · answered Apr 20 '18 at 16:52

8

You have to set the imageDimsWhenDisabled property of the corresponding button cell:

button.isEnabled = false
if let cell = button.cell as? NSButtonCell {
    cell.imageDimsWhenDisabled = false
}

answered Apr 20 '18 at 16:52

Jean-Baptiste Yunès

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1

Thank you. It serves the purpose. – bisma Apr 23 '18 at 04:15

score 0 · Answer 2 · answered Apr 20 '18 at 16:36

0

One option would be instead of disabling it you can let it fire and handle it accordingly in code. such as do nothing when condition to disable applies.

answered Apr 20 '18 at 16:36

XP.

52
7

There is more than one button overlapping. I need to disable one type of buttons otherwise it will eat the touch event of the button behind. Can't do that. – bisma Apr 20 '18 at 16:53

score 0 · Answer 3 · answered Apr 20 '18 at 16:38

As this answer says, override NSButton and return nil for hitTest(_:).

If you want to toggle whether user interaction is enabled, create a custom variable and return super.hitTest(point) if you want the button to be enabled.

class CustomButton: NSButton {
    var isUserInteractionEnabled = true

    override func hitTest(_ point: NSPoint) -> NSView? {
        return isUserInteractionEnabled ? super.hitTest(point) : nil
    }
}

Disable NSButton without grayed image

3 Answers3