how to split arrays inside a big array to fit intersect function?

Question

I have the following array that contains other arrays:

$bigArray = [$array_one, $array_two, $array_three,.... ];

I want to array_intersect the inner arrays like so:

$intersect = array_intersect($array_one, $array_two, $array_three,....);

How do I handle it?

[check this for other options](https://stackoverflow.com/questions/38056228/get-intersection-of-a-multiple-array-in-php) — kofi_codes, Apr 17 '18 at 15:37

Don't Panic · Accepted Answer · 2018-04-17T15:44:51.400

4

Like this:

$intersect = array_intersect(...$bigArray);

The ... operator, introduced in PHP 5.6, allows you to use an array to pass multiple function arguments.

It's also possible to do this with call_user_func_array, but argument unpacking offers some advantages over that approach.

edited Apr 17 '18 at 15:44

answered Apr 17 '18 at 15:17

Don't Panic

call_user_func_array('array_intersect', $bigArray); this also works for me – Soliman Mahmoud Soliman Apr 17 '18 at 15:35
3

@SolimanMahmoudSoliman yes, before PHP 5.6, that was the standard way to do this. You can check out the RFC for more info: https://wiki.php.net/rfc/argument_unpacking, specifically the "Advantages over call_user_func_array" section. – Don't Panic Apr 17 '18 at 15:38

score 1 · Answer 2 · answered Apr 17 '18 at 15:34

1

call_user_func_array('array_intersect', $bigArray);

this works for me

answered Apr 17 '18 at 15:34

2 Answers2