Print from specific elements in python tuple

Question

Am trying to print elements of index 1 like 4994 2993 100 20.5 from my tuple but it print ('dan', '2993').

b = (("ben","4994"),("dan","2993"),("Hans",100),("Frank",20.5))


print(b[1])

Have searched on this site and none of the answer provided gives me clue to solve this.

Your code behaves correctly - it is printing the first element of your tuple as you say. — Psytho, Mar 28 '18 at 13:36

score 2 · Answer 1 · answered Mar 28 '18 at 13:34

2

You can use unpacking in a list comprehension:

b = (("ben","4994"),("dan","2993"),("Hans",100),("Frank",20.5))
new_b = [i for _, i in b]

Output:

['4994', '2993', 100, 20.5]

answered Mar 28 '18 at 13:34

Ajax1234

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Austin · Answer 2 · 2020-05-15T14:35:04.533

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Another list comprehension way:

b = (("ben","4994"),("dan","2993"),("Hans",100),("Frank",20.5))
new_b = [i[1] for i in b]
# ['4994', '2993', 100, 20.5]

edited May 15 '20 at 14:35

answered Mar 28 '18 at 13:36

Austin

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lpozo · Answer 3 · 2018-03-28T15:42:13.333

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b = (("ben","4994"),("dan","2993"),("Hans",100),("Frank",20.5))

for item in b:
    print(item[1])

In this case you are trying to access the second element of a two-items tuple. Using slicing would be:

>>> b[0][1]

and you will get as output>

>>> '4994'

If you put this tuple into a for loop, the first element (item in my code) would be: ("ben","4994") and when you print(item[1]) you are having access to the second level of slicing, that is: '4994' in the first running of the loop and so on.

edited Mar 28 '18 at 15:42

answered Mar 28 '18 at 13:36

lpozo

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While this code may answer the question, providing additional context regarding **how** and/or **why** it solves the problem would improve the answer's long-term value. – Alexander Mar 28 '18 at 15:33

Print from specific elements in python tuple

3 Answers3