How to solve Luke: error java.lang.RuntimeException: No valid directory at the location when trying to open lucene index directory?

Asked Mar 27 '18 at 13:40

Active Mar 27 '18 at 13:40

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Im trying to read/analyze the index files but I get the error below when i try to open the lucene index directory

[2018-03-27 18:12:33,424] ERROR (LukeController.java:181) - Failed to open index: /Users/tucker/lux/2018/03/27/1522108807
java.lang.RuntimeException: No valid directory at the location: /Users/tucker/lux/2018/03/27/1522108807

Inside the directory /Users/tucker/lux/2018/03/27/1522108807 i have files below

_1y.cfe         _84.cfe         _c2.cfe         _c4.cfe         _c6.cfe         _c8.cfe
_1y.cfs         _84.cfs         _c2.cfs         _c4.cfs         _c6.cfs         _c8.cfs
_1y.si          _84.si          _c2.si          _c4.si          _c6.si          _c8.si
_51.cfe         _c1.cfe         _c3.cfe         _c5.cfe         _c7.cfe         index.properties
_51.cfs         _c1.cfs         _c3.cfs         _c5.cfs         _c7.cfs         optimized_flag
_51.si          _c1.si          _c3.si          _c5.si          _c7.si          segments_10

Luke version 7.2.0 github

asked Mar 27 '18 at 13:40

sherpaurgen

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it's strange that 7.2 Luke do not contain LukeController.java class, are you sure, that you're running correct version? – Mysterion Mar 29 '18 at 09:00
I used luke 6.0.0 and was able to see index – sherpaurgen Mar 29 '18 at 10:26
so, you are using 6.0.0 version and everything is working? or you want to use 7.2? What's your problem? – Mysterion Mar 29 '18 at 10:39
I used ver 6.0.0 and everything is working – sherpaurgen Mar 29 '18 at 18:03

How to solve Luke: error java.lang.RuntimeException: No valid directory at the location when trying to open lucene index directory?

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