How to sort a list using comparator in Descending order (based on salary which is a long value)

Question

class Empl{

    private String name;
    private long salary;

    public Empl(String n, long s){
        this.name = n;
        this.salary = s;
    }

    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public long getSalary() {
        return salary;
    }
    public void setSalary(long salary) {
        this.salary = salary;
    }

}

this is already covered here : https://stackoverflow.com/questions/21626439/how-to-implement-the-java-comparable-interface — user9405863, Mar 15 '18 at 07:22

Youcef LAIDANI · Accepted Answer · 2018-03-15T08:46:36.560

4

If you are using Java 8 you can use Stream#sorted with Comparator#comparingLong like this :

list = list.stream()
        .sorted(Comparator.comparingLong(Empl::getSalary).reversed())
        .collect(toList());

Note the .reversed() when you use it the list is sorted descendant, else if you don't use it, it is sorted ascendant.

edited Mar 15 '18 at 08:46

answered Mar 15 '18 at 07:24

Youcef LAIDANI

55,661
15
90
140

Minor, but you’ve got your ascending and descending words mixed up. It should be the reciprocal of what you’ve mentioned. Also it’s better to use Comparator.conparingLong to avoid the overhead of boxing and unboxing. – Ousmane D. Mar 15 '18 at 08:41

score 1 · Answer 2 · edited Mar 15 '18 at 09:44

Try this:

Descending

Collections.sort(modelList, new Comparator<Empl>() {
        @Override
        public int compare(Empl o1, Empl o2) {
            return o2.getSalary().compareTo(o1.getSalary());
        }
});

Ascending

Collections.sort(modelList, new Comparator<Empl>() {
            @Override
            public int compare(Empl o1, Empl o2) {
                return o1.getSalary().compareTo(o2.getSalary());
            }
});

score 0 · Answer 3 · edited Mar 15 '18 at 08:05

0

Use this way

Collections.sort(employeeList, new Comparator<VariationsItem>() {
    @Override
    public int compare(Empl lhs, Empl rhs) {
        return ((Long) rhs.getSalary()).compareTo((Long) lhs.getSalary());
    }
});

edited Mar 15 '18 at 08:05

slavoo

5,798
64
37
39

answered Mar 15 '18 at 07:23

Ramkumar.M

681
6
21

score 0 · Answer 4 · answered Mar 15 '18 at 08:47

0

If you’re using Java-8 then you can call the default sort method directly on the list providing the necessary comparator.

list.sort(Comparator.comparingLong(Empl::getSalary).reversed());

answered Mar 15 '18 at 08:47

Ousmane D.

54,915
8
91
126

How to sort a list using comparator in Descending order (based on salary which is a long value)

4 Answers4