How do i filter character that occurs more than 1 time using regex in Java?

Question

I need a regex string that remove the duplicated characters that occurs more than 1 time.

for example :

eve -> e and v
eev -> e and v

i found one that like this : (.)(?=\\1)

that regex can remove duplicated characters that adjacent like : eev -> e and v

but that regex can not remove the second e after v in "eve" word.

So you want to remove repeats of a letter in a word, so eve and eev both become ev? — Lance Toth, Mar 12 '18 at 12:38
exactly, so even though the word is like this : evevvveeeve its still become e and v only — Kaze Nakazawa, Mar 12 '18 at 12:41
Then this is a duplicate. Check @MalteHartwig comment above. — revo, Mar 12 '18 at 12:46
sorry for the duplication, i've been searching for hours on so many site (including this site) but return to no avail. thank you for referencing that answer @revo. the answer is exactly what i want. — Kaze Nakazawa, Mar 12 '18 at 12:51

score 0 · Answer 1 · answered Mar 12 '18 at 12:42

0

If you are using Java 8 you can use :

String result = str.chars()
        .mapToObj(c -> String.valueOf((char) c))
        .distinct()
        .collect(Collectors.joining());

I/O

eve         -> ev
eev         -> ev
evevvveeeve -> ev

answered Mar 12 '18 at 12:42

Youcef LAIDANI

1 Answers1