In constructor method references, difference between using generic type parameters and not?

Question

I'm reading Effective Java 3 and noticed this code in Item 43: “Prefer method references to lambdas”:

TreeMap<K,V>::new

Notice the type parameters. I've always just done:

TreeMap::new

I use Intellij and have never gotten a warning about this or any recommendation to change it. In fact, when I have the IDE change the above method reference into a lambda it converts it to

() -> new TreeMap<Integer, Integer>()

What is the value in including the type parameters? Can't the compiler infer it based on the type parameters of the variable? Based on how the IDE transformed the method reference into a lambda it seems like it can.

It usually can. For the occasions it can't, that's how you do it. — Louis Wasserman, Mar 09 '18 at 18:46
It can usually be inferred, but I've found it necessary in the past. — shmosel, Mar 09 '18 at 18:47

score 5 · Accepted Answer · edited Jun 20 '20 at 09:12

The constructor reference TreeMap::new is the same as using diamond type inference (§15.13.1):

For convenience, when the name of a generic type is used to refer to an instance method (where the receiver becomes the first parameter), the target type is used to determine the type arguments. This facilitates usage like Pair::first in place of Pair<String,Integer>::first.

Similarly, a method reference like Pair::new is treated like a "diamond" instance creation (new Pair<>()). Because the "diamond" is implicit, this form does not instantiate a raw type; in fact, there is no way to express a reference to the constructor of a raw type.

You'd need to provide type arguments explicitly in more or less the same situations as when you would need to provide type arguments to a constructor explicitly.

For example, in the following, the call to get prevents the return assignment from being considered during inference of supplier, so T is inferred to be ArrayList<Object>:

class Example {
    public static void main(String[] args) {
        ArrayList<String> list =
            supplier(ArrayList::new).get(); // compile error
    }
    static <T> Supplier<T> supplier(Supplier<T> s) { return s; }
}

In that contrived example, we'd have to use ArrayList<String>::new.

In constructor method references, difference between using generic type parameters and not?

1 Answers1