Why doesn't count($var) = 0 indicate the variable is empty?

Asked Mar 07 '18 at 00:54

Active Mar 07 '18 at 00:54

Viewed 40 times

I have a variable $outvar that is returned from a call to a COM object. The following,

echo count($outvar)

returns a value of 0.

But if I

echo $outvar[1][1];

the value that I expect to be passed back by the COM object is printed.

Why doesn't a count of 0 indicate that there is nothing in the variable?

(Note: I believe $outvar is a VARIANT containing 2 numbers, although I cannot be sure. This question is related to another question specifically regarding Displaying contents of VARIANT in PHP, that is yet to be answered.)

asked Mar 07 '18 at 00:54

Phil Goddard

10,571
1
16
28

what is the content of $outvar? – Madhawa Priyashantha Mar 07 '18 at 00:58
1

Can you show us the result of this: `var_dump($outvar)` – Kerkouch Mar 07 '18 at 00:58
@Fast Snail - unfortunately I can't show you the content of `$outvar`. My other question that I link to specifically deals with me not being able to view the variable contents (which I cannot do, except for the first element which I can view using the 2nd code line in the question). – Phil Goddard Mar 07 '18 at 01:29
@Karkouch - the output of `var_dump($outvar)` is `object(variant)#2 (0) { }`. – Phil Goddard Mar 07 '18 at 01:30

Why doesn't count($var) = 0 indicate the variable is empty?

0 Answers0