Python networking : find MAC address for corresponding interfaces

Question

I has found a scripts from pmav99. Big thanks to him.

import socket
import psutil

def get_ip_addresses(family):
    for interface, snics in psutil.net_if_addrs().items():
        for snic in snics:
            if snic.family == family:
                yield (interface, snic.address, snic.netmask)

ipv4s = list(get_ip_addresses(socket.AF_INET))

print ipv4s

The result is :

[('Local Area Connection* 2', '169.254.189.147', '255.255.0.0'), ('Ethernet', '192.168.18.34', '255.255.255.0'), ('Wi-Fi', '192.168.1.102', '255.255.255.0'), ('Loopback Pseudo-Interface 1', '127.0.0.1', '255.0.0.0')]

But in net_if_addrs() of psutil, it also provide mac-address of each interfaces. So how can i add the mac address to the list ? the keys name of MAC address also is address. I can't find the way to get it.

score 3 · Answer 1 · answered Mar 06 '18 at 14:27

i find a simply way to get the result that i want

import socket
import psutil

def get_ip_addresses(family):
    for interface, snics in psutil.net_if_addrs().items():
        for snic in snics:
            if snic.family == -1 :
                mac = snic.address
            if snic.family == 2 :
                yield (interface, snic.address, snic.netmask, mac)

ipv4 = list(get_ip_addresses(socket.AF_INET))

print ipv4

and the result look like this :

[('Local Area Connection* 2', '169.254.189.147', '255.255.0.0', '34-F3-9A-4C-D0-C5'), ('Ethernet', '192.168.18.34', '255.255.255.0', 'C8-5B-76-AC-B7-BC'), ('Wi-Fi', '192.168.1.106', '255.255.255.0', '34-F3-9A-4C-D0-C4'), ('Loopback Pseudo-Interface 1', '127.0.0.1', '255.0.0.0', '00-00-00-00-00-00-00-E0')]

Connection name with corresponding ipv4, netmask and mac address. Hope it helpful for orther visitor :).

Robᵩ · Accepted Answer · 2018-03-05T23:49:35.067

2

According to the documentation, MAC addresses are noted by family psutil.AF_LINK. This code fragment will get a list of interface names, along with the MAC addresses.

macs = list(get_ip_addresses(psutil.AF_LINK))
print macs

The following program will produce a mapping from MAC addresses to IPV4 addresses:

import socket
import psutil

def get_ip_addresses(family):
    for interface, snics in psutil.net_if_addrs().items():
        for snic in snics:
            if snic.family == family:
                yield (interface, (snic.address, snic.netmask))

ipv4s = dict(get_ip_addresses(socket.AF_INET))
macs = dict(get_ip_addresses(psutil.AF_LINK))
mac2ipv4 = {macs[k][0]: ipv4s[k] for k in set(macs) & set(ipv4s)}

print mac2ipv4

edited Mar 05 '18 at 23:49

answered Mar 05 '18 at 23:40

Robᵩ

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Thanks Rob, but i also need interface name too. I find a way to do that is simply add **if** to it. if snic.family == -1 : mac = snic.address if snic.family == 2 : yield (interface, snic.address, snic.netmask, mac) – Park Yo Jin Mar 06 '18 at 00:01
If you don't mind, please post your solution as an answer. Then, if you decide to use it, accept your own answer (yes, that is allowed). By posting it as an answer, future [SO] visitors may be helped. – Robᵩ Mar 06 '18 at 00:09

Python networking : find MAC address for corresponding interfaces

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