invalid json response in php when json response inside json response

Question

i have try to print json response but "" are added to my json response

i tried below code php and id generated by drupal field

<?php
$data = array("title"=>"test","body"=>"test body");
$php = json_encode($data,JSON_FORCE_OBJECT);
echo json_encode(array("php"=>$php,"id"=>10));
?>

output :

{"php":"{\"title\":\"test\",\"body\":\"test body\"}","id":10}

but i want output like below

{"php":{"title":"test","body":"test body"},"id":10}

i added some more code for above problem

{"php":"{\"title\":\"test\",\"body\":\"test body\"}","id":10}

why not remove json_encode from echo json_encode($php);

how i can get above output` second time

why doenvote ? see my code first – Bhargav Chudasama Mar 01 '18 at 11:37 — Bhargav Chudasama, Mar 01 '18 at 11:37
@mickmackusa see my edited code – Bhargav Chudasama Mar 01 '18 at 11:39 — Bhargav Chudasama, Mar 01 '18 at 11:39

Syscall · Answer 1 · 2018-03-01T12:34:44.687

3

You're encoding in JSON two times :

$data = array("title"=>"test","body"=>"test body");
$php = json_encode($data,JSON_FORCE_OBJECT);
echo $php ; // remove json_encode() here

After question edit:

$data = array("title"=>"test","body"=>"test body");
echo json_encode(array("php"=>$data,"id"=>10));

edited Mar 01 '18 at 12:34

answered Mar 01 '18 at 11:34

Syscall

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@Bhargav No need to json_encode, just add $data in your initial array. `$data=['title'=>'test'];$array=['php'=>$data,'id'=>10];echo json_encode($array);` – Syscall Mar 01 '18 at 11:41
1

@Bhargav do all of your array modifications before encoding. Add all relevant question details to your question as an edit – mickmackusa Mar 01 '18 at 11:45
@Bhargav So, decode, insert, encode : `$array=json_decode($json,true);$array['php']=$data;echo json_encode($array);` – Syscall Mar 01 '18 at 11:45
but i can only `print or echo` the output not set inside code because `global php` take output inside `''(single quate)` – Bhargav Chudasama Mar 01 '18 at 11:48
i tried your suggest code but output like `[ { "php": "Array", "nid": "8075" } ]` – Bhargav Chudasama Mar 01 '18 at 11:58
@Bhargav Did you solve your issue ? Did you check the updated anwser? – Syscall Mar 01 '18 at 13:28
you know about `drupal` because problem generated in drupal – Bhargav Chudasama Mar 01 '18 at 13:41

Keyur · Answer 2 · 2018-03-01T12:03:12.290

0

You can also simply do this,

<?php
    $data = array("title"=>"test","body"=>"test body");
    echo json_encode(array("php"=>$data,"id"=>10));
?>

edited Mar 01 '18 at 12:03

answered Mar 01 '18 at 11:36

Keyur

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@Bhargav What exactly you want? – Keyur Mar 01 '18 at 11:57

invalid json response in php when json response inside json response

2 Answers2