Get datatype of input variable in the command line Php

Question

This is my code.

$fr = fopen("php://stdin", "r");
$input = fgets($fr);


if (preg_match('/^-?[0-9]{1,4}$/', $input)) {
    echo "Integer.";
} else if (preg_match('/^[-+]?[0-9]*\.?[0-9]+$/', $input)) {
    echo "Float.";
} else if (preg_match('/[a-zA-Z\s]^[0-9]/', $input)) {
    echo "string.";
}

I will get the $input variable from the command line entered. I need to find what datatype the variable is either int, float, string.

Tried gettype() method but it is always string. So only tried with preg_match.

Although in this also i am not getting the correct output.

Ex: 1.2e3 i am getting as string

Everything that comes from stdin is a string. Also, what is your question? — u_mulder, Mar 01 '18 at 08:13
Do you know in advance what are the possible types you can receive? — Aerendir, Mar 01 '18 at 08:15
For ex if the $input has only numbers then i need to find that the variable holds only integer. Suppose if it has float value then i need to check it is float — Parithiban, Mar 01 '18 at 08:15

score 0 · Answer 1 · answered Mar 01 '18 at 08:17

All input from the command line (or any pipe for that matter) will always be a string, since no other types are supported. What you want to figure out is whether your string is numeric and then convert it to a number:

if (is_numeric($input)) {
    $input = +$input;
}

The unary + operator will cause the string to be interpreted as a number and result either in an int or float.

Get datatype of input variable in the command line Php

1 Answers1