I would like linearizate the product of two float variables. Suppose that a model has the product x * y, where x and y are float, with 0 <= x <= 1 and 0 <= y <= 1. How linearizate this product?
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What do you mean by linearize? Or was it linearizate? – Mad Physicist Feb 28 '18 at 03:17
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Also, what language? Cplex offers a number of alternatives to my understanding, and float can mean different things. – Mad Physicist Feb 28 '18 at 03:20
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1I am building a mathematical model on cplex, using c++, and I would like linearizate a constraint that has the product of two continuous variables. I have a constraint x * y (product of two variables), where domain this variable are 0 <= x <= 1 and 0 <= y <= 1. Linearizate is to transform this expression (x * y) into something that does not exist the multiplication of two variables – Ernando Gomes Feb 28 '18 at 03:40
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1Thanks for the clarification. Have you actually tried anything or done any research of your own? – Mad Physicist Feb 28 '18 at 04:22
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1I don't think you can exactly linearise that. You can approximate it with e.g. piecewise linear expressions. – TimChippingtonDerrick Feb 28 '18 at 07:14
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Quadratic solvers are developed for a reason. – Erwin Kalvelagen Feb 28 '18 at 12:01
1 Answers
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I gave an example in OPL/CPLEX here What you can do is remember that
4*x*y=(x+y)*(x+y)-(x-y)(x-y)
So if you do a variable change X=x+y and Y=x-y
x*y
becomes
1/4*(X*X-Y*Y)
which is separable.
And then you are able to interpolate the function x*x by piecewise linear function:
// y=x*x interpolation
int sampleSize=10000;
float s=0;
float e=100;
float x[i in 0..sampleSize]=s+(e-s)*i/sampleSize;
int nbSegments=20;
float x2[i in 0..nbSegments]=(s)+(e-s)*i/nbSegments;
float y2[i in 0..nbSegments]=x2[i]*x2[i];
float firstSlope=0;
float lastSlope=0;
tuple breakpoint // y=f(x)
{
key float x;
float y;
}
sorted { breakpoint } breakpoints={<x2[i],y2[i]> | i in 0..nbSegments};
float slopesBeforeBreakpoint[b in breakpoints]=
(b.x==first(breakpoints).x)
?firstSlope
:(b.y-prev(breakpoints,b).y)/(b.x-prev(breakpoints,b).x);
pwlFunction f=piecewise(b in breakpoints)
{ slopesBeforeBreakpoint[b]->b.x; lastSlope } (first(breakpoints).x, first(breakpoints).y);
assert forall(b in breakpoints) f(b.x)==b.y;
float maxError=max (i in 0..sampleSize) abs(x[i]*x[i]-f(x[i]));
float averageError=1/(sampleSize+1)*sum (i in 0..sampleSize) abs(x[i]*x[i]-f(x[i]));
execute
{
writeln("maxError = ",maxError);
writeln("averageError = ",averageError);
}
dvar float a in 0..10;
dvar float b in 0..10;
dvar float squareaplusb;
dvar float squareaminusb;
maximize a+b;
dvar float ab;
subject to
{
ab<=10;
ab==1/4*(squareaplusb-squareaminusb);
squareaplusb==f(a+b);
squareaminusb==f(a-b);
}

Alex Fleischer
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See https://github.com/AlexFleischerParis/howtowithopl/blob/master/multiply2float.mod in https://www.linkedin.com/pulse/how-opl-alex-fleischer/ – Alex Fleischer Jan 15 '23 at 08:06