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I found that I cant easely write bounding box using 4 points (x, y, w, h) using opencv. Where x, y is top left corner and w=width, h=height.

cv2.rectangle(img,(x,y),(x+w,y+h),(255,0,0),15)

But How is it possible to write bounding box using opencv having only xmax xmin ymax ymin points? I need to check that all is allright in my code and bounding boxes used by x, y, w, h is completely equal to bounding boxes that I have under xmax xmin ymax ymin.

I converted x, y, w, h to xmax xmin ymax ymin using these code 

bbox_topleft_corner_x = int(prod_data[0])
bbox_topleft_corner_y = int(prod_data[1])
bbox_w = int(prod_data[2])
bbox_h = int(prod_data[3])

ymax = bbox_topleft_corner_y
ymin = bbox_topleft_corner_y - bbox_h
xmax = bbox_topleft_corner_x + bbox_w
xmin = ymin + bbox_w

But I'm not sure that I did all as I wanted. I wanted to convert x, y, w, h to VOOC2007 annotation xml format and their bounding box format

Thanks for any advice

Ivan Shelonik
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2 Answers2

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Given x, y, width, and height, it should be trivial to get x_max and y_max.

x_max = x + width
y_max = y + height

It is important to remember the coordinate system for images starts with (0, 0) in the top left, and (image_width, image_height) in the bottom right. Therefore:

top_left = (x, y)
bottom_right = (x+w, y+h)

The last thing to remember is that there are some cases were the parameter requested is a point (x, y), such as the case in the cv2.rectangle function. However, pixels are accessed as the underlying ndarray structure image[row, column]

Check out this question for more info about opencv coordinate systems.

Hal Jarrett
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I guess your problem is the reference system.

In a image the point (0,0) is the top left pixel. Judging from your ymin calculation it seems you're considering y "the upper is the higher" but with an origin in top-left point is exactly the opposite.

Moia
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