Regex lazy on non-capturing group

Question

I have this regex:

(?:(?:AND\sNOT|AND|OR)(?!.*(?:AND\sNOT|AND|OR))\s)(.*)

What I want is to get the last key:value pair, example -

k:v AND k1:v1 AND NOT k2:v2 OR k3:v3

I want the regex to match k3:v3, and it does, but it doesn't match the key:value in the next situation -

k:v

I need it to match the key:value pair even if it's the first one and there's no operators brefore...

update: key:value is not the issue here, I need it to match everything after the last operator

update 2: tried to do the following -

(?:(?:AND\sNOT|AND|OR)?(?!.*(?:AND\sNOT|AND|OR))\s)(.*)
(?:(?:AND\sNOT|AND|OR?)(?!.*(?:AND\sNOT|AND|OR))\s)(.*)

didn't work

Maybe [`(?:.*(?:AND\sNOT|AND|OR)\s)?(.*)$`](https://regex101.com/r/jAeS6o/2) — Srdjan M., Feb 25 '18 at 13:01

Jeto · Accepted Answer · 2018-02-25T15:08:40.173

2

Edit - My bad, \K isn't supported in JS. Here's an alternative one:

/(?:.*(?:AND|OR|NOT)\s+)?(.*)/ (group 1)

https://regex101.com/r/AyVV89/3 (Please check the matches on the right panel, for some reason group 1 isn't highlighted on the text.)

Original post

Per your last update (that wasn't obvious at all before you mentioned it):

key:value is not the issue here, I need it to match everything after the last operator

This one will match anything after the last operator, no matter what it is (and work without an operator too):

/(?:.*(?:AND|OR|NOT)\s+\K)?.*/

edited Feb 25 '18 at 15:08

answered Feb 25 '18 at 14:59

Jeto

Javascript doesn't support `\K`. – revo Feb 25 '18 at 15:00
You're right, didn't realize that. Will edit/delete my answer then, thanks. – Jeto Feb 25 '18 at 15:02

revo · Answer 2 · 2018-02-25T15:05:11.093

1

Update

As per comments, I assume you need to match last key:value pair along with its operator if any, and anything that comes after:

(?:.*\b(AND(?:\sNOT)?|OR) +)?(\S+:\S+.*)

What you need could be simplified into this:

(?:AND(?:\sNOT)?|OR)\s+(\S+)$

edited Feb 25 '18 at 15:05

answered Feb 25 '18 at 13:31

revo

Your regex is not working as expected: https://regex101.com/r/JXXjWk/2 – Nadav Shabtai Feb 25 '18 at 14:10
Well are you seeking for `\S+$`? [Look at this demo](https://regex101.com/r/yniN74/1). – revo Feb 25 '18 at 14:13
No, your regex is not including white spaces event if it's not operator between them.. look at my question again.. anyway S.Jovan posted the correct regex – Nadav Shabtai Feb 25 '18 at 14:15
https://regex101.com/r/yniN74/2 it matches the last word, not everything after the operator... I need the operators to be the separator, not white spaces – Nadav Shabtai Feb 25 '18 at 14:30
So you need everything after last key:value pair? here `asd asd`? – revo Feb 25 '18 at 14:36
https://regex101.com/r/jAeS6o/5 Now it's not grouping the values, it selects the operators too – Nadav Shabtai Feb 25 '18 at 15:42

AndreyS Scherbakov · Answer 3 · 2018-02-25T13:33:50.707

0

From your explanation, you don't need the first operator at all. Simply try

(?!.*(?:NOT|AND|OR)\s)(\b.*)

edited Feb 25 '18 at 13:33

answered Feb 25 '18 at 13:07

3 Answers3