UIApplication not opening url

Question

I am grabbing the URL from a struct and sending it to a UITapGesture, and I tried printing it(it prints URL), but it doesn't want to actually open the URL.

@objc func getUrl(sender: UITapGestureRecognizer){
    guard  let url = self.rssUrl else { return }
    print(url)
    UIApplication.shared.open(url, options: [:], completionHandler: nil)
}

Grabbing an URL here

var rssUrl: URL?

var item: RSSItem! {
    DispatchQueue.global(qos: .userInteractive).async {
        //other code

        let store_Article = Article(dict: ["text": sum, "rssUrl": rssLink])
        storedArticle.append(store_Article)

        let data = dataUrl.init(articleUrl: store_Article).someUrl

        DispatchQueue.main.sync {
            //other code
        }
    }
}

Edit

it prints: http:/www.instyle.com/news/rihanna-30th-birthday-party -- file:///

for an example

How many accounts do you have now in the last couple of days? This is at least three. Why? — rmaddy, Feb 22 '18 at 04:27
@rmaddy just 3 it keeps banning me from asking questions even after a week — , Feb 22 '18 at 04:37
@rmaddy I had an account that was doing well, then all of a sudden stack banned me from asking — , Feb 22 '18 at 04:41

Kamlesh Shingarakhiya · Accepted Answer · 2018-02-22T04:49:38.467

0

Try with this EDIT

@objc func getUrl(sender: UITapGestureRecognizer)
{
    guard let url = URL(string: YOUR_URL_STRING) else {
        return //be safe
    }

    if #available(iOS 10.0, *) {
        UIApplication.shared.open(url, options: [:], completionHandler: nil)
    } else {
        UIApplication.shared.openURL(url)
    }
}

edited Feb 22 '18 at 04:49

answered Feb 22 '18 at 04:24

Kamlesh Shingarakhiya

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this doesn't work it gives an error type, the URL is type URL – Feb 22 '18 at 04:40
I checked its working fine. Please check EDIT answer – Kamlesh Shingarakhiya Feb 22 '18 at 04:50
Yw! Happy coding!! – Kamlesh Shingarakhiya Feb 22 '18 at 05:02

UIApplication not opening url

1 Answers1