getc() skips first value of text file (C)

Question

I am trying to read a text file separated by semicolons such as

3;7;9;

4;7;23;

However, every time I call

while ((c = getc(fp))!= EOF) 

     putchar(c);

it skips the first value (3) and only outputs:

;7;9;

4;7;23;

Is there any way to get the first value?

Thank you

Show some [MCVE]. Compile your actual code with all warnings and debug info (`gcc -Wall -Wextra -g` with [GCC](http://gcc.gnu.org/)). Use the [`gdb` debugger](https://sourceware.org/gdb/onlinedocs/gdb/). Current question is off-topic on StackOverflow — Basile Starynkevitch, Feb 19 '18 at 06:07

score 0 · Answer 1 · answered Feb 19 '18 at 06:11

using C Program.*/

include

int main(){

//file nane
const char *fileName="sample.txt";
//file pointer
FILE *fp;
//to store read character
char ch;

//open file in read mode
fp=fopen(fileName,"r");
if(fp==NULL){
    printf("Error in opening file.\n");
    return -1;
}
printf("Content of file\n");
while((ch=getc(fp))!=EOF){
    printf("%c",ch);
}
fclose(fp);

return 0;

}

getc() skips first value of text file (C)

1 Answers1

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