Counting the occurrences of a character in each element of a list

Question

     lst = ['10010001','01101001']

I need to count the number of times the number '1' appears in each element

What have you tried? Where are you getting stuck? What's your desired output? — pault, Feb 18 '18 at 15:37

score 0 · Answer 1 · answered Feb 18 '18 at 15:39

0

for element in lst:
    print element.count("1")

answered Feb 18 '18 at 15:39

Sebastien D

score 0 · Answer 2 · answered Feb 18 '18 at 15:40

0

>>> lst = ['10010001','01101001']
>>> [l.count('1') for l in lst]
[3, 4]

answered Feb 18 '18 at 15:40

bla

score -1 · Answer 3 · answered Feb 18 '18 at 15:39

-1

from collections import Counter
num_of_1s = [Counter(item)['1'] for item in lst]

answered Feb 18 '18 at 15:39

Louis Barto

3 Answers3