I need to verify what ip address is announce the default route:
set command [ exec "show ip route" ]
the ouput:
Codes: L - local, C - connected, S - static, R - RIP, M - mobile, B - BGP
D - EIGRP, EX - EIGRP external, O - OSPF, IA - OSPF inter area
N1 - OSPF NSSA external type 1, N2 - OSPF NSSA external type 2
E1 - OSPF external type 1, E2 - OSPF external type 2
i - IS-IS, su - IS-IS summary, L1 - IS-IS level-1, L2 - IS-IS level-2
ia - IS-IS inter area, * - candidate default, U - per-user static route
o - ODR, P - periodic downloaded static route, H - NHRP, l - LISP
+ - replicated route, % - next hop override
Gateway of last resort is 10.17.1.252 to network 0.0.0.0
B* 0.0.0.0/0 [200/0] via 10.17.1.252, 01:16:22
10.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C 10.17.1.0/24 is directly connected, FastEthernet1/0
L 10.17.1.253/32 is directly connected, FastEthernet1/0
172.22.0.0/32 is subnetted, 1 subnets
C 172.22.12.250 is directly connected, Loopback1
172.26.0.0/16 is variably subnetted, 3 subnets, 2 masks
B 172.26.69.64/30 [200/0] via 10.17.1.252, 01:16:33
C 172.26.70.64/30 is directly connected, FastEthernet0/0
L 172.26.70.66/32 is directly connected, FastEthernet0/0
I need to find this: "0.0.0.0/0 [200/0] via 10.17.1.252", but this address: 10.17.1.252 can change, how I can put a variable in a regex ?
set routes [ regexp {(0.0.0.0\/0 \[200\/0\] via $bgp_neighbor)} $command match default_route ]