I have the following code snipet:
// code snipet one:
#include <memory>
#include <iostream>
#include <queue>
struct A {
uint32_t val0 = 0xff;
~A() {
std::cout << "item gets freed" << std::endl;
}
};
typedef std::shared_ptr<A> A_PTR;
int main()
{
std::queue<A_PTR> Q;
Q.push(std::make_shared<A>());
auto && temp_PTR = Q.front();
std::cout << "first use count = " << temp_PTR.use_count() << std::endl;
Q.pop();
std::cout << "second use count = " << temp_PTR.use_count() <<std::endl;
return 0;
}
After running it, I got the result as following:
first use count = 1
item gets freed
second use count = 0
Q1: is anybody can explain what the type of temp_PTR after the third line of main function is called?
if I change that line as
A_PTR && temp_PTR = Q.front();
compiler complains that
main.cpp: In function 'int main()':
main.cpp:26:32: error: cannot bind '__gnu_cxx::__alloc_traits > >::value_type {aka std::shared_ptr}' lvalue to 'A_PTR&& {aka std::shared_ptr&&}'
A_PTR && temp_PTR = Q.front();
Q2: I remember that the return value of a function should be a r-value, but it seems here the compiler tell me: " hey, the return value of Queue.front() is a l-value", why is here?