Linux Bash: Run php script located in different folder

Question

What I attempt: php folder/file I get command not found

The PHP location is /usr/local/bin/php-7.0

`/usr/local/bin/php-7.0 folder/file`. To avoid `command not found` later, add `/usr/local/bin` to your `$PATH` variable. — Viktor Khilin, Feb 02 '18 at 12:35
@Syscall it returns pretty much nothing `php [user@example.com curerentfolder]` — RWS, Feb 02 '18 at 12:37
Possible duplicate of [-bash: php: command not found - Centos6.7](https://stackoverflow.com/questions/37994827/bash-php-command-not-found-centos6-7) — Viktor Khilin, Feb 02 '18 at 12:39

score 1 · Accepted Answer · answered Feb 02 '18 at 12:37

1

The executable seems to be named php-7.0:

$ /usr/local/bin/php-7.0 /path/to/file.php

Instead of call the fully qualified path, you could make sure that /usr/local/bin is in your $PATH, e.g.:

$ export PATH=${PATH}:/usr/local/bin

and then call php-7.0:

$ php-7.0 /path/to/file.php

answered Feb 02 '18 at 12:37

Mureinik

And maybe a `ln -s` to link `php` to `php-7.0`? – Syscall Feb 02 '18 at 12:40
@Syscall or even `alias`, or better yet, use `alternatives`. – Mureinik Feb 02 '18 at 12:41

1 Answers1