fizz buzz game in python

Question

Write a simple function called fizzBuzz that takes in a positive integer, and returns ‘fizz’, ‘buzz’, ‘fizzbuzz’ or the argument it receives, based on the following:

Returns ‘fizz’ if the argument is divisible by 3
Returns buzz if the argument is divisible by 5
Returns ‘fizzBuzz’ if the argument is divisible by 3 and 5
Returns the argument itself if it is NOT divisible by 3 or 5
Returns exactly 'Invalid Argument' when an invalid argument is passed.

Examples: Input Output
3 "fizz"
5 "buzz"
15 "fizzBuzz"

i tried out this code but it didnt work

def fizz_buzz(n):
    n = []
    for nums in n:
        if nums % 5 == 0 and nums % 3 == 0:
            print("fizz buzz")
        elif nums % 3 == 0:
            print("fizz")
        elif nums % 5 == 0:
            print("buzz")
        elif nums % 3 != 0 and nums % 5 != 0:
            print(nums)
        else:
            print("invalid argument")

Answer 1

easiest way I think:

def fizz_buzz(input):
    if (input % 3 == 0) and (input % 5 == 0):
        return 'FizzBuzz'
    if input % 3 == 0:
        return 'Fizz'
    if input % 5 == 0:
        return 'Buzz'
    return input

print(fizz_buzz(3))

PS: change print(fizz_buzz(3)) with any number to test it

Answer 2

here is one way you might do it ;P

from itertools import islice,count

targets = [3,5,15,22]
for target_value in targets:
    fizzbuzz = ("".join("BzuzzizF"[::2 * j] for j in (-1, 1) if 1 > i % (4 + j)) or i for i in count(1) )
    print(target_value,"=",next(islice(fizzbuzz,target_value-1,target_value+3)))

Answer 3

I wrote this to do it. It uses a dictionary to make it easy to modify it.

multiples = {3 : 'Fizz', 5 : 'Buzz'}
for i in range (1, 101):
    output = ''
    for j in multiples.keys():
        if i % j == 0:
            output += str(multiples.get(j))    
    if output == '':
        output = str(i)

    print (output)

If you change the dictionary to something like multiples = {3 : 'Fizz', 5 : 'Buzz', 7 : 'Fuzz'} it'll still work

Answer 4

Because of having to be a list I would do it somewhat like that:

def fizz_buzz(n):
    for nums in n:
        if nums % 5 == 0 and nums % 3 == 0:
            print("fizz buzz")
        elif nums % 3 == 0:
            print("fizz")
        elif nums % 5 == 0:
            print("buzz")
        elif nums % 3 != 0 and nums % 5 != 0:
            print(nums)
        else:
            print("invalid argument")


my_list = []

while True:
    user_input = input('Enter the Number: ')
    if user_input != 'exit':
         my_list.append(int(user_input))
    else:
        break

fizz_buzz(my_list)

In the Bottom part, I generate a list. You didn't provide any information about where you get your numbers from...so take that if you need it. But the fizz_buzz function now definitely works

Answer 5

Here's your Code

def fizz_buzz(n):
   
  if (n % 3 == 0) and (n % 5 == 0):
    return 'FizzBuzz'
    
  if n % 3 == 0:
    return 'Fizz'

  if n % 5 == 0:
    return 'Buzz'

  return n

print(fizz_buzz(6))

Answer 6

here's mine

 def fizz_buzz(input):


    if (input % 3 == 0) and (input % 5 == 0):
        return "fizz_buzz"
    if input % 5 == 0:
        return "Buzz"
    if input % 3 == 0:
        return "fizz"
    return input

print(fizz_buzz(int(input("Enter your number:"))))

here's my answer it will return the same number if you input numbers that are not divisible to 3 and 5 and you can also input any number.

Answer 7

def fizzbuzz(n):

    if n % 3 == 0 and n % 5 == 0:
        print('FizzBuzz')
    elif n % 3 == 0:
        print('Fizz')
    elif n % 5 == 0:
        print('Buzz')
    else:
        return str(n)

n=int(input("Enter number:"))

fizzbuzz(n)

this works...