meta multiple operator overloading

Question

The question is if I can find a way to make a parametrized overloading of an operator i.e. instead of

template <class T>
class A
{
   private:
       T m_var;
   public:
       operator T () const { return m_var; }
       const A operator+ ( const A& r_var ) const { return m_var + r_var; }
       const A operator- ( const A& r_var ) const { return m_var - r_var; }
       const A operator* ( const A& r_var ) const { return m_var * r_var; }
       const A operator/ ( const A& r_var ) const { return m_var / r_var; }
   ...........
}

to have something like this

template <class T>
class A
{
   private:
       T m_var;
   public:
       operator T () const { return m_var; }
       const A operator 'X' ( const A& r_var ) const { return m_var 'X' r_var; }

   ...........
}

where 'X' will take values +, -, *, /, and in this way to avoid repetition of the same pattern code. Thanks in advance.

How could it be done using macro? thank you – Feb 01 '11 at 19:31 — , Feb 01 '11 at 19:31

score 2 · Answer 1 · answered Jan 30 '11 at 17:42

2

Check out boost::operators. It requires += and *= to be defined by you. The rest(+,-,*,/,-=,/=) are defined by the library. It also works for binary operators.

answered Jan 30 '11 at 17:42

rymurr

444
4
11

score 0 · Answer 2 · answered Jan 30 '11 at 17:55

0

This isn't possible within templates. You will need to write a macro.

Also, you should not return a const rvalue, because it's perfectly legal to call non-const methods on rvalues of class type.

answered Jan 30 '11 at 17:55

Puppy

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meta multiple operator overloading

2 Answers2