Here is my C program with one static, two global, one local and one extern variable.
#include <stdio.h>
int gvar1;
int gvar2 = 12;
extern int evar = 1;
int main(void)
{
int lvar;
static int svar = 4;
lvar = 2;
gvar1 = 3;
printf ("global1-%d global2-%d local+1-%d static-%d extern-%d\n", gvar1, gvar2, (lvar+1), svar, evar);
return 0;
}
Note that gvar1, gvar2, evar, lvar and svar are all defined as integers.
I disassembled the code using objdump and the debug_str for this shows as below:
Contents of section .debug_str:
0000 76617269 61626c65 732e6300 6c6f6e67 variables.c.long
0010 20756e73 69676e65 6420696e 74002f75 unsigned int./u
0020 73657273 2f686f6d 6534302f 72616f70 sers/home40/raop
0030 2f626b75 702f6578 616d706c 65730075 /bkup/examples.u
0040 6e736967 6e656420 63686172 00737661 nsigned char.sva
0050 72006d61 696e006c 6f6e6720 696e7400 r.main.long int.
0060 6c766172 0073686f 72742075 6e736967 lvar.short unsig
0070 6e656420 696e7400 67766172 31006776 ned int.gvar1.gv
0080 61723200 65766172 00474e55 20432034 ar2.evar.GNU C 4
0090 2e342e36 20323031 31303733 31202852 .4.6 20110731 (R
00a0 65642048 61742034 2e342e36 2d332900 ed Hat 4.4.6-3).
00b0 73686f72 7420696e 7400 short int.
Why is it showing the following?
unsigned char.svar
long int.lvar
short unsigned int.gvar1.gvar2.evar
How does GCC decide which type it should be stored as?
I am using GCC 4.4.6 20110731 (Red Hat 4.4.6-3)