How get string before symbol

Question

I have strings

TEST #1 - Description
TEST #2 / Description
...

I need get string before # but with #1, output: TEST #1

strstr($str, '#', true);

These code output: TEST i need TEST #1

I think it is posible with preg_match but i dont know how make. — Shoxa, Jan 22 '18 at 21:26
@rtfm: Yes, however I anticipated the _"but sometimes there is no space"_ or _"doesn't work for `TEST-#1`"_. — AbraCadaver, Jan 22 '18 at 21:37
@Shoxa please explain the variability of your input data, so that we can provide an accurate method without "guessing" what your strings look like. Can we possibly use `^[^-/]+(?= )`? — mickmackusa, Jan 22 '18 at 21:40
you may assume what you like, ill base any answer on the actual code provided @AbraCadaver — , Jan 22 '18 at 21:40
or `^\D+\d+` ? It is best to give us realistic sample input data. — mickmackusa, Jan 22 '18 at 21:47
@Shoxa If you are satisfied with AbraCadaver's answer please mark it with the green tick. If you would like to receive more answers/support, please improve your question by addressing the comments/concerns under your question. — mickmackusa, Jan 25 '18 at 01:18

AbraCadaver · Answer 1 · 2018-01-23T20:14:14.340

If the format is consistent (word space # digits) then:

$parts  = explode(' ', $str);
$result = $parts[0] . ' ' . $parts[1];

I assume the number can be multiple digits, so you'll need regex:

preg_match('/[^#]+#\d+/', $str, $match);
echo $match[0];

If you need multiple from one string then:

preg_match_all('/[^#]+#\d+/', $str, $matches);
print_r($matches[0]);

Either way you are matching:

1 Answers1