Parsing HHMMSS come from NMEA

Question

I have a trouble with NMEA data(gpzda). The problem is explained below.

NMEA Data : $GPZDA,011856.00,17,03,2018,,*61

My Parsing Code.

char hour[2] = { 0 };
for (int i=0; i < 2; i++) hour[i] = utctime[i];
info.tm_hour = atoi(hour);

char min[2] = { 0 };
for (int i=0; i < 2; i++) min[i] = utctime[i + 2];
info.tm_min = atoi(min);

char sec[2] = { 0 };
for (int i=0; i < 2; i++) sec[i] = utctime[i + 4];
info.tm_sec = atoi(sec);

cout << info.tm_year << " | " << info.tm_mon << " | " << info.tm_mday << " | " << info.tm_hour << " | " << info.tm_min << " | " << info.tm_sec << endl;

The code is well working, but some time the hour value is strange like a "126". I thought that "6" is add from another memory. How to parse this data to well work?

score 1 · Accepted Answer · answered Jan 17 '18 at 01:31

1

You should zero terminate your strings, so declare each one to be of size 3.

char hour[3] = { 0 };

and so on

answered Jan 17 '18 at 01:31

Sid S

6,037
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Why..? hour[0], hour[1] is used. so hour[2] = {0} is right? – spritecodej Jan 17 '18 at 01:42
Wrong. Accessing`hour[2]` yields undefined behavior when you declare the string to have size 2. – Sid S Jan 17 '18 at 01:50

Parsing HHMMSS come from NMEA

1 Answers1