7

I have written some logic in MySQL stored procedure.I am using spring boot with hibernate. I have a login procedure with IN OUT parameters. From my login procedure I want to pass message to user. But i don't know how to call stored procedure in Spring boot. My code is bellow..

  1. My Login Procedure is

    CREATE PROCEDURE login(IN  in_user_id    varchar(100),
                               IN  in_password   varchar(100),
                               OUT out_code      INT,
                               OUT out_message   varchar(100))
     BEGIN
        IF in_user_id IS NULL OR in_user_id = ''
         THEN
         SET out_code = 1;
         SET out_message = 'Please Enter Your First Name.';
       END IF;
     /*Logi Here*/
    
     END;
    
  2. I have used entity class like

    @Entity
    @Table(name = "user")
     @NamedStoredProcedureQueries({
       @NamedStoredProcedureQuery(
       name = "do_login", 
       procedureName = "login", 
       resultClasses = { LoginModel.class },    
       parameters = { 
          @StoredProcedureParameter( name = " in_user_id",  type = String.class,  mode = ParameterMode.IN),
          @StoredProcedureParameter( name = "in_password",  type = String.class,  mode = ParameterMode.IN),
          @StoredProcedureParameter( name = "out_code",  type = Integer.class,  mode = ParameterMode.OUT), 
          @StoredProcedureParameter( name = "out_message",  type = String.class,  mode = ParameterMode.OUT)
    
         }),
    
     })
    
     public class LoginModel implements Serializable {
    
       @NotEmpty
       private String userid;
    
       @NotEmpty
       private String password;
    
      //Here is getter setter
      }
    
  3. In My Login Controller I want to call my procedure so that i can forward my user to dashboard.If user enter wrong user id or password , i want to show message from procedure. I have used bellow code in my login controller

    @RequestMapping(value = "/login", method = RequestMethod.POST)
     public String doLogin(@ModelAttribute("webLoginForm") @Valid LoginModel registrationModel,
        BindingResult bindingResult, Model model, Errors error) {
         if(error.hasErrors()) {
             return "login";
         }
    
       // Here I want to check My Procedure result & redirect to welcome page
       //return "redirect:/welcome";
    
      return "login";
    }
    
  4. I have used repository but it did not write anything here. I have used repository bellow like..

       public interface LoginRepository  extends CrudRepository<LoginModel, Integer>{
    
    
     }
    
Enamul Haque
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4 Answers4

19

You can call a stored procedure using javax.persistence.StoredProcedureQuery. You dont even need to declare anything on your entity.
I'd suggest moving the procedure calling logic to a service and then call the service method from your controller.

For instance:

@Service
public class LoginServiceImpl implements LoginService {

    @PersistenceContext
    private EntityManager entityManager;

    public Boolean checkUsernameAndPassword(String username, String password) {

        //"login" this is the name of your procedure
        StoredProcedureQuery query = entityManager.createStoredProcedureQuery("login"); 

        //Declare the parameters in the same order
        query.registerStoredProcedureParameter(1, String.class, ParameterMode.IN);
        query.registerStoredProcedureParameter(2, String.class, ParameterMode.IN);
        query.registerStoredProcedureParameter(3, Integer.class, ParameterMode.OUT);
        query.registerStoredProcedureParameter(4, String.class, ParameterMode.OUT);

        //Pass the parameter values
        query.setParameter(1, username);
        query.setParameter(2, password);

        //Execute query
        query.execute();

        //Get output parameters
        Integer outCode = (Integer) query.getOutputParameterValue(3);
        String outMessage = (String) query.getOutputParameterValue(4);

        return true; //enter your condition
    }
}

And then, you can call this method from your Controller, after injecting your LoginService.

lzagkaretos
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  • I tried this out, but it doesn't work for me. Somehow I always get `null` as OutputParameterValue. I already post something on this. Maybe you can help me out with it? https://stackoverflow.com/questions/57527592/stored-procedure-in-java-spring-boot-project-returns-null-as-output – Constantin Beer Aug 17 '19 at 04:04
4

Try this simple solution , I use Spring boot and Sql Server- In your Repository

1) with no parameter

@Query(value = "{call yourSpName()}", nativeQuery = true) List<Map<String, Object>> methodName();

2) with Parameter

@Query(value = "{call yourSpName(:param1)}", nativeQuery = true) List<Map<String, Object>> methodName(@Param("param1")Long param1);

VAIBHAV NERLE
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0

You can try this method to call procedure from Spring

import java.util.HashMap;
import java.util.Map;
import oracle.jdbc.driver.OracleTypes;
import org.springframework.jdbc.core.JdbcTemplate;
import org.springframework.jdbc.core.SqlOutParameter;
import org.springframework.jdbc.core.SqlParameter;
import org.springframework.jdbc.core.simple.SimpleJdbcCall;

public class MainApplicationMethod 

{

public static void main(String[] args) throws Exception {

    JdbcTemplate jdbcTemplate = new JdbcTemplate();

    SimpleJdbcCall jdbcCall = new SimpleJdbcCall(jdbcTemplate).withProcedureName("procedureName");
    jdbcCall.addDeclaredParameter(new SqlParameter("parameter1", OracleTypes.VARCHAR));
    jdbcCall.addDeclaredParameter(new SqlOutParameter("outParam1",OracleTypes.VARCHAR));
    String value=null;
    Map<String, String> callParams = new HashMap<String, String>();
    callParams.put("parameter1", value);

    Map<String, Object> outputMap = jdbcCall.execute(callParams);
}

}

0

This works for me using jdbctempate

   SimpleJdbcCall jdbcCall =  new SimpleJdbcCall(jdbcTemplate).withProcedureName("your procedure name");

    Map<String, Object> inParamMap = new HashMap<>();

    inParamMap.put("input of your procedure", value of input);

    SqlParameterSource in = new MapSqlParameterSource(inParamMap);

    Map<String, Object> call = jdbcCall.execute(in);
Ahmed Shalash
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