How to display Image from dataGridView by Selected the Row and show the image to pictureBox in C# WindowsForm

Question

How to display Image from dataGridView by Selected the Row and show the image to pictureBox in C# WindowsForm

Problem: Cannot retrieve image from datagridView to pictureBox.

I Tried the Code Below how to display image on picture box by Select from the dataGridView which has been save on a database as byte. But Errors Occurs as that System.String cannot cast to system.Byte and When I Tried the other code it Says Invalid Argument Here is My Code Below:

1. DataGridview using Mouse Click Event to display the values and image when select data on DataGridView
2. Show how I Browse Picture from the system and upload to pictureBox
3. Show how I save image from Picture Box to Database.

I hope You Get my problem and help me solve this issue.

private void dataGridView1_MouseClick(object sender, MouseEventArgs e)
     {
       try
       {
            label21.Text = dataGridView1.SelectedRows[0].Cells["M_FirstName"].Value.ToString();
            textBox1.Text = dataGridView1.SelectedRows[0].Cells[0].Value.ToString();
            textBox2.Text = dataGridView1.SelectedRows[0].Cells[1].Value.ToString();
            textBox3.Text = dataGridView1.SelectedRows[0].Cells[2].Value.ToString();
            comboBox1.Text = dataGridView1.SelectedRows[0].Cells[3].Value.ToString();
            dateTimePicker1.Text = dataGridView1.SelectedRows[0].Cells[4].Value.ToString();
            textBox6.Text = dataGridView1.SelectedRows[0].Cells[5].Value.ToString();
            textBox7.Text = dataGridView1.SelectedRows[0].Cells[6].Value.ToString();
            textBox8.Text = dataGridView1.SelectedRows[0].Cells[7].Value.ToString();
            textBox9.Text = dataGridView1.SelectedRows[0].Cells[8].Value.ToString();
            textBox10.Text = dataGridView1.SelectedRows[0].Cells[9].Value.ToString();

    //First try to select image from datagridview and display to picturebox
            byte[] image = Encoding.ASCII.GetBytes(dataGridView1.SelectedRows[0].Cells[10].Value.ToString());
            if (image == null)
                pictureBox1.Image = null;
            else
            {
                    var ms= new MemoryStream(image);
              //Error is Invalid Argument (ms)
                    pictureBox1.Image = Image.FromStream(ms);
            }

    //Second try to select image from datagridview and display to picturebox
    //When I tried this code below the Error shows that "*Unable to Cast Object of type 'System.String' to type 'System.Byte[]'*"

            var data = (Byte[])(dataGridView1.SelectedRows[0].Cells[10].Value);
            var stream = new MemoryStream(data);
            pictureBox1.Image = Image.FromStream(stream);

    //Both the Code Above does not work to select image from datagridview and display on picturebox
    //How can I do to make it work.
}
catch(Exception ex)
{
    MessageBox.Show(ex.Message);
}
    }

*****My Code to upload Image to pictureBox*****

Code to Browse Image

try
        {
            OpenFileDialog dialog = new OpenFileDialog();
            dialog.Filter = "*.jpg files(*.jpg)|*.jpg| PNG files(*.png)|*.png| All Fies(*.*)|*.*";

            if (dialog.ShowDialog() == System.Windows.Forms.DialogResult.OK)
            {
                imagelocation = dialog.FileName;
                pictureBox1.ImageLocation = imagelocation;
            }

        }
        catch (Exception)
        {
            MessageBox.Show("An Error Occured", "Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
        }

******My Code to Save Image to database*****

Code to Save Image to DataBase

try
        {

            if (textBox2.Text == "" || textBox3.Text == "" || comboBox1.Text == "" || textBox6.Text == "" || textBox7.Text == "" || textBox8.Text == "" || textBox9.Text == "" || textBox10.Text == "")
            {
                MessageBox.Show("Please Fill all the fields !");
            }
            else
            {

                byte[] image = null;
                FileStream Streem = new FileStream(imagelocation, FileMode.Open, FileAccess.Read);
                BinaryReader brs = new BinaryReader(Streem);
                image = brs.ReadBytes((int)Streem.Length);



                con.Open();

                String qry = "Insert Into membership_tbl values('" + textBox2.Text + "','" + textBox3.Text + "','" + comboBox1.Text + "','" + dateTimePicker1.Text + "','" + textBox6.Text + "','" + textBox7.Text + "','" + textBox8.Text + "','" + textBox9.Text + "','" + textBox10.Text + "',@image)";

                cmd = new SqlCommand(qry, con);
                cmd.Parameters.Add(new SqlParameter("@image", image));
                cmd.ExecuteNonQuery();
                con.Close();
                MessageBox.Show("Member Added ! ");
                clear();
                Membership mem = new Membership();
                mem.Show();
                this.Hide();
            }

        }
        catch (Exception ex)
        {
            MessageBox.Show(ex.Message);
        }