how can I send json instead of form-data to my symfony controller

Question

there a tons of tutorials on the web about how to set the action-response to type json in a symfony controller. But how can I receive JSON?

$request->getRequestFormat() returns "json", but the json data seems to be lost, because $request->getParameter() doesn't work.

This is my routing:

importservice:
  url: /importservice
  class: sfRequestRoute
  param: { module: remoteaccess, action: import, sf_format: json }
  requirements:
    sf_method: post
    sf_format: json

Edit:

getParameter() decodes multipart/form-data (html-forms) and get-parameters, so I thought it also does this for content-type application/json. I need this for a web-service which posts data. My basic idea was that it makes no difference whether a human fills out html-forms or a bot sends the data directly. I thought that encoding the content to json is easier to implement than encoding it to multipart/form-data.

It's unclear what you mean, please elaborate. – Maerlyn Jan 27 '11 at 18:28 — Maerlyn, Jan 27 '11 at 18:28
Why do you need to send data in JSON? – Darmen Amanbay Jan 28 '11 at 05:25 — Darmen Amanbay, Jan 28 '11 at 05:25

score 1 · Accepted Answer · answered Jan 28 '11 at 21:16

I came to this conclusion:

Symfony's getParameter() method provides GET-parameters (url) and parameters which are defined in the routing (uri). The items of multipart data will also be provided, because this media-type is just a container for sub-content packages, whereas application/json is already the content itself. In other words: multipart just declares that there is more than one content-package.

One might claim that json is also a data-container, but I think that multipart contains data on the "http-level", whereas json contains data on the "content-level".

The confusion arises by the fact that multipart is actually something like a meta-media-type.

how can I send json instead of form-data to my symfony controller

1 Answers1