How can I get method's "args" argument value in while using ipdb?

Question

In ipdb using command a or args prints information on provided arguments for the method. How do I get actual args variable so I can work on the provided data?

For example when I have code:

class A(object):
    def test(*args, **kwargs):
        import ipdb; ipdb.set_trace()


A().test('testing arg')

Then after running the code I tried:

ipdb> args
args = (<__main__.A object at 0x1007bdf90>, 'testing arg')
kwargs = {}
ipdb> args[0]
args = (<__main__.A object at 0x1007bdf90>, 'testing arg')
kwargs = {}
ipdb>

http://frid.github.io/blog/2014/06/05/python-ipdb-cheatsheet/ from there is looks like "p args" might work. — Tom Dalton, Jan 08 '18 at 13:20

score 11 · Accepted Answer · answered Jan 08 '18 at 13:20

11

Prefix your command with ! to disable the pdb magic.

ipdb> !args

answered Jan 08 '18 at 13:20

Daniel Roseman

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score 0 · Answer 2 · answered Jul 12 '18 at 15:30

0

I often set dummy variables which are part of pdb magic and then use those

ipdb> aa = args

answered Jul 12 '18 at 15:30

The Doctor

334
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11

How can I get method's "args" argument value in while using ipdb?

2 Answers2