If I set a variable in my middleware, how do I make that available to my views in my views.py?

Question

This is my middleware:

class Go():
    def process_view(self, request, view_func, view_args, view_kwargs):
        aaa = "hello"
        return None

If I go into my views.py and print aaa, I get an error.

Let's just assume you're kidding about this question as written. Perhaps you could provide some real code to provide a real context for this question. — S.Lott, Jan 26 '11 at 19:22
It's kind of important, when programming (or stitching together swathes of others' code), to be able to distinguish a local variable from other types of variable. — johnsyweb, Jan 26 '11 at 21:57
@S.Lott: Here's the context -- http://stackoverflow.com/q/4808664/78845 — johnsyweb, Jan 26 '11 at 22:26
@Johnsyweb: It's kind of important, when programming (or stitching together swathes of others' code), to be able to make design decisions, write code and do some debugning without posting every single step of the process as a question on Stack Overflow. — S.Lott, Jan 26 '11 at 23:05
@Johnsyweb: One step at a time is good. Actually doing the work oneself is better. — S.Lott, Jan 27 '11 at 02:49

score 1 · Answer 1 · answered Jan 26 '11 at 19:33

1

Try

request.aaa = "hello"

and then in your view:

print request.aaa

answered Jan 26 '11 at 19:33

sunn0

score 1 · Accepted Answer · answered Jan 26 '11 at 19:33

1

If you want it available in your views, you can add anything you want to the request object as that's ultimately passed down to your views.

request.myvar = 'hello'

answered Jan 26 '11 at 19:33

Is there a way I can just do "myvar" instead of request.myvar? – TIMEX Jan 26 '11 at 20:04

2 Answers2