How to check image open without error using url in php?

Asked Dec 29 '17 at 09:32

Active Dec 29 '17 at 09:37

Viewed 114 times

I need to check image open without error using url , When am open the image it got the message like cannot be displayed image because it contains errors.

So I got error like imagecreatefromjpeg(): gd-jpeg: JPEG library reports unrecoverable error when resize image that's why am plan to check image open without error or not before resize image.

Am tried like below code,

$url = "path/to/sample.jpg"

if(file_exits($url)) {
    echo "image exits" 
} else {
    echo "image not exists"
}

But this not working always came else part only. and also am tried like,

getimagesize($url)

but this also not worked got size in that image but it have some errors in image.

Please give me solution for my problem.

edited Dec 29 '17 at 09:37

MCMXCII

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asked Dec 29 '17 at 09:32

Geetha Janarthanan

`@getimagesize($url)` used this for temporary solution – Bilal Ahmed Dec 29 '17 at 09:37
i have faced the same problem. if you use `getimagesize()` it will consume more memory on server. that's why i have used `file_exits($url)`. – Ayyappa amara Dec 29 '17 at 09:38
Might be worth giving this a read https://stackoverflow.com/questions/10611883/warning-imagejpeg-functionimagejpeg-gd-jpeg-jpeg-library-reports-unrecov – MCMXCII Dec 29 '17 at 09:38
what output are you getting by using `print_r(@getimagesize($external_link))`? – Prateik Darji Dec 29 '17 at 09:57
Got getimage result like Array ( [0] => 37 [1] => 55 [2] => 2 [3] => width="37" height="55" [bits] => 8 [channels] => 3 [mime] => image/jpeg ) – Geetha Janarthanan Dec 29 '17 at 09:59

How to check image open without error using url in php?

0 Answers0