I have a data frame, for example:
name age
1 "Danny" 20
2 "Mitt" 35
3 "Dylan" 8
When I get new entry, I want to update this df.
I have used nrow(df) + 1 for the next row:
df[nrow(df) + 1, ] <- c("Tom", 4)
Is there any other way to do this?
You may use rbind:
rbind(df,list("Tom",4))
check for ?rbind:
The functions cbind and rbind are S3 generic, with methods for data frames. The data frame method will be used if at least one argument is a data frame and the rest are vectors or matrices. There can be other methods; in particular, there is one for time series objects. See the section on ‘Dispatch’ for how the method to be used is selected. If some of the arguments are of an S4 class, i.e., isS4(.) is true, S4 methods are sought also, and the hidden cbind / rbind functions from package methods maybe called, which in turn build on cbind2 or rbind2, respectively. In that case, deparse.level is obeyed, similarly to the default method.
In the default method, all the vectors/matrices must be atomic (see vector) or lists. Expressions are not allowed. Language objects (such as formulae and calls) and pairlists will be coerced to lists: other objects (such as names and external pointers) will be included as elements in a list result. Any classes the inputs might have are discarded (in particular, factors are replaced by their internal codes).
If there are several matrix arguments, they must all have the same number of columns (or rows) and this will be the number of columns (or rows) of the result. If all the arguments are vectors, the number of columns (rows) in the result is equal to the length of the longest vector. Values in shorter arguments are recycled to achieve this length (with a warning if they are recycled only fractionally).
Let me suggest you the add_row function from the tibble package. You could do it simply as follows:
df = add_row (df, name="Tom", age=4)
