Alternate ways in place of zip

Question

I have below inputs,

inp = 'Sample'
n = 5

I would like to generate a list of tuples of n elements packing input with index. So that my output is,

[('Sample', 0), ('Sample', 1), ('Sample', 2), ('Sample', 3), ('Sample', 4)]

Below snippet does the work neat,

output = zip([inp]*n, range(n))

Just curious about alternate approaches to solve the same?

Ah!!! That's really simple and neat than with `zip` ! Thanks!! — Vivek Harikrishnan, Dec 19 '17 at 11:22

score 2 · Accepted Answer · answered Dec 19 '17 at 11:23

The most obvious solution (a list comprehension) has already been mentioned in the comments, so here's an alternative with itertools.zip_longest, just for fun -

from itertools import zip_longest

r = list(zip_longest([], range(n), fillvalue=inp))
print(r)
[('Sample', 0), ('Sample', 1), ('Sample', 2), ('Sample', 3), ('Sample', 4)]

On python2.x, you'd need izip_longest instead.

score 0 · Answer 2 · answered Dec 24 '17 at 14:30

0

inp='sample'
n=5
print [(inp,i) for i in range(n)]

it Shows O/P as:

[('sample', 0), ('sample', 1), ('sample', 2), ('sample', 3), ('sample', 4)]

answered Dec 24 '17 at 14:30

Sagar T

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list comprehension is good way to solve the problem over zip function? – Sagar T Dec 25 '17 at 05:14

Alternate ways in place of zip

2 Answers2