When using hashing you set the size of your output matrix in advance. You did so by setting hash_size = 2 ^ 14. This stays the same indpendently of the ngram window specified in the model. However, the counts within the output matrix change.
(In response to below comments:) Below you find a minimum example with two very simple strings to demonstrate the different outputs for two different ngram windows used in a hash_vectorizer. For the bigrams case I have added the output matrix of a vocab_vectorizer for comparison. You realize that you have to set a hash size sufficiently large to account for all terms. If it is too small the hash values of individual terms may collide.
Your comment concerning that you always have to compare the outputs of a vocab_vectorizer approach and a hash_vectorizer approach leads into the wrong direction, because you would then loose the efficiency/memory advantage that might be generated by a hashing approach, which avoids generating a vocabulary. Depending on your data and desired output hashing may treat accuracy (and interpretability of terms in the dtm) against efficiency. Hence, it depends on your use case if hashing is reasonable or not (which it is especially for classification tasks at the document level for large collections).
I hope this gives you a rough idea about hashing and what you can or cannot expect from it. You might also check some posts on hashing at quora, Wikipedia (or also here). Or also refer to the detailed original sources listed on text2vec.org.
library(text2vec)
txt <- c("a string string", "and another string")
it = itoken(txt, progressbar = F)
#the following four example demonstrate the effect of the size of the hash
#and the use of signed hashes (i.e. the use of a secondary hash function to reduce risk of collisions)
vectorizer_small = hash_vectorizer(2 ^ 2, c(1L, 1L)) #unigrams only
hash_dtm_small = create_dtm(it, vectorizer_small)
as.matrix(hash_dtm_small)
# [,1] [,2] [,3] [,4]
# 1 2 0 0 1
# 2 1 2 0 0 #collision of the hash values of and / another
vectorizer_small_signed = hash_vectorizer(2 ^ 2, c(1L, 1L), signed_hash = TRUE) #unigrams only
hash_dtm_small = create_dtm(it, vectorizer_small_signed)
as.matrix(hash_dtm_small)
# [,1] [,2] [,3] [,4]
# 1 2 0 0 1
# 2 1 0 0 0 #no collision but some terms (and / another) not represented as hash value
vectorizer_medium = hash_vectorizer(2 ^ 3, c(1L, 1L)) #unigrams only
hash_dtm_medium = create_dtm(it, vectorizer_medium)
as.matrix(hash_dtm_medium)
# [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8]
# 1 0 0 0 1 2 0 0 0
# 2 0 1 0 0 1 1 0 0 #no collision, all terms represented by hash values
vectorizer_medium = hash_vectorizer(2 ^ 3, c(1L, 1L), signed_hash = TRUE) #unigrams only
hash_dtm_medium = create_dtm(it, vectorizer_medium)
as.matrix(hash_dtm_medium)
# [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8]
# 1 0 0 0 1 2 0 0 0
# 2 0 -1 0 0 1 1 0 0 #no collision, all terms represented as hash values
#in addition second hash function generated a negative hash value
#the following two examples deomstrate the difference between
#two hash vectorizers one with unigrams, one allowing for bigrams
#and one vocab vectorizer with bigrams
vectorizer = hash_vectorizer(2 ^ 4, c(1L, 1L)) #unigrams only
hash_dtm = create_dtm(it, vectorizer)
as.matrix(hash_dtm)
# [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13] [,14] [,15] [,16]
# 1 0 0 0 0 0 0 0 0 0 0 0 1 2 0 0 0
# 2 0 0 0 0 0 0 0 0 0 1 0 0 1 1 0 0
vectorizer2 = hash_vectorizer(2 ^ 4, c(1L, 2L)) #unigrams + bigrams
hash_dtm2 = create_dtm(it, vectorizer2)
as.matrix(hash_dtm2)
# [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13] [,14] [,15] [,16]
# 1 1 0 0 1 0 0 0 0 0 0 0 1 2 0 0 0
# 2 0 0 0 0 0 1 1 0 0 1 0 0 1 1 0 0
v <- create_vocabulary(it, c(1L, 2L))
vectorizer_v = vocab_vectorizer(v) #unigrams + bigrams
v_dtm = create_dtm(it, vectorizer_v)
as.matrix(v_dtm)
# a_string and_another a another and string_string another_string string
# 1 1 0 1 0 0 1 0 2
# 2 0 1 0 1 1 0 1 1
sum(Matrix::colSums(as.matrix(hash_dtm)) > 0)
#[1] 4 - these are the four unigrams a, string, and, another
sum(Matrix::colSums(hash_dtm2) > 0)
#[1] 8 - these are the four unigrams as above plus the 4 bigrams string_string, a_string, and_another, another_string
sum(Matrix::colSums(v_dtm) > 0)
#[1] 8 - same as hash_dtm2
