I have a long running process which I need to start. It takes a few seconds to start, and outputs logs to stdout, with one that indicates it is ready.
I would like to:
- start the process silently, so that the stdout from the process is not displayed in my session.
- capture the output as it streams so that I can determine that it is ready.
- have some handle on the process so that I can stop the process at a later point.
I have come close using Shelly, Turtle and System.Process, but fail to capture the stdout.
Using System.Process I had:
import Control.Concurrent (threadDelay)
import Control.Concurrent.Async (race)
import System.IO
import System.Process
startService :: IO ProcessHandle
startService = do
let cmd = "./my-service"
args = [ "-p 1234" ]
(_, Just hout, _, p) <- createProcess $ (proc cmd args) { std_out = CreatePipe }
started <- either id id <$> race (checkStarted hout) timeOut
unless started $ fail "Service not started"
pure p
where
checkStarted :: Handle -> IO Bool
checkStarted h = do
str <- hGetLine h
-- check str for started log, else loop
timeOut :: IO Bool
timeOut = do
threadDelay 10000000
pure False
But The handler hout
was never in a ready state.
Using Shelly I had:
import Control.Concurrent (threadDelay)
import Control.Concurrent.Async (race)
import Control.Concurrent.MVar
import Shelly
import System.IO
startService :: IO (Async ())
startService = do
let cmd = "./my-service"
args = [ "-p 1234" ]
startedMVar <- newEmptyMVar
async <- shelly $ asyncSh $ runHandle cmd args $ recordWhenStarted startedMVar
started <- either id id <$> race (readMVar startedMVar) timeOut
unless started $ fail "Service not started"
pure async
where
recordWhenStarted :: MVar Bool -> Text -> IO ()
recordWhenStarted mvar txt =
when (isStartedLog txt) $
modifyMVar_ mvar (const $ pure True)
timeOut :: IO Bool
timeOut = do
threadDelay 10000000
pure False
But the recordWhenStarted
is never called.