I'm trying to compute tangent line (or tangent vector) at 3D point of a 3D curve. The problem is how to compute the slope according to x,y and z at point ? I recall that for a 2D curve, the equation of the tangent line is:
tang=(x-x_k)*slope_k+y_k
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Maybe you should ask this on https://math.stackexchange.com/. Here should be only programming questions – Vadim Kotov Dec 12 '17 at 15:28
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I want to program this to have the tangent at my 3D point on python.. – javier Dec 12 '17 at 15:32
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Do you have the equation of the curve or is it a series of points? – meowgoesthedog Dec 12 '17 at 21:07
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Yes, I have the coordinates (x,y,z) of all the points of the 3D curve – javier Dec 13 '17 at 09:47
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The slope in 3D can be written as simple different between two 3D points. Here is why: https://math.stackexchange.com/questions/799783/slope-of-a-line-in-3d-coordinate-system
javier
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